Answer:
Correct option is D)
Let the particle of mass m be placed on A Then,
F
1
=
(2R)
2
GMm
4R
When a spherical part of radius R/2 is taken out from the big sphere,
then the mass of remaining sphere becomes-
=[
3
4πR
−
4π
(
R
)
]d=
[
8
7
7M
[∴M=
]
Now force on m place at A.F
8×9R
GMm.4
GMm(18−4)
4
×
9R
9
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Answers & Comments
Answer:
Correct option is D)
Let the particle of mass m be placed on A Then,
F
1
=
(2R)
2
GMm
=
4R
2
GMm
When a spherical part of radius R/2 is taken out from the big sphere,
then the mass of remaining sphere becomes-
=[
3
4πR
3
−
3
4π
(
2
R
)
3
]d=
3
4πR
3
[
8
7
]d=
8
7M
[∴M=
3
4πR
3
]
Now force on m place at A.F
2
=
4R
2
GMm
−
8×9R
2
GMm.4
=
8×9R
2
GMm(18−4)
=
4
7
×
9R
2
GMm
F
2
F
1
=
4
7
×
9R
2
GMm
4R
2
GMm
=
7
9