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alihusain40
@alihusain40
June 2021
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please factorise question number 6 7 8 9 10 and 11 and and please explain
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sanjaysingh10941
Answer:
Here is your answer
Step-by-step explanation:
(vi)6a⁴b²-18a²b³
=6a²b²(a²-3b)
(vii)2ax²+6a²x
=2ax(x+3a)
(viii)a³-6a²
=a²(a-3)
(ix)6a⁴b²-18a²b²
=6a²b²(a²-3)
(x)ax²+a²y²
=a(x²+ay²)
(xi)3p²y²-6pyx+9x³p
=3p(py²-2yx+3x³)
Hope it will help you
1 votes
Thanks 1
suzanejazinth
Answer:
1 votes
Thanks 1
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Answers & Comments
Answer:
Here is your answer
Step-by-step explanation:
(vi)6a⁴b²-18a²b³
=6a²b²(a²-3b)
(vii)2ax²+6a²x
=2ax(x+3a)
(viii)a³-6a²
=a²(a-3)
(ix)6a⁴b²-18a²b²
=6a²b²(a²-3)
(x)ax²+a²y²
=a(x²+ay²)
(xi)3p²y²-6pyx+9x³p
=3p(py²-2yx+3x³)
Hope it will help you
Answer: