Let BQ be the first tower with height 30 m

Angle of elevation, ∠QAB = 60°

Let PA be the second tower with height h m

Angle of elevation, ∠PBA = 30°

AB is the distance between the two towers.

In triangle AQB,

By pythagorean theorem,

tan 60° = QB/AB

By trigonometric ratio of angles,

tan 60° = √3

So, √3 = 30/AB

AB = 30/√3 m

AB = 3(10)/√3

AB = 10√3 m

Therefore, the distance between two towers is 10√3 m.

In triangle APB,

By using pythagorean theorem,

tan 30° = AP/AB

By trigonometric ratio of angles,

tan 30° = 1/√3

So, 1/√3 = AP/(30/√3)

AP = (30/√3)/√3

AP = 30/3

AP = 10 m

Therefore, the height of the second tower is 10 m.

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