Four resistors of 16 Ω each are connected in parallel, and another four resistors of 16 Ω each are connected in series.
The total resistance.
For connection in series,
For connection in parallel,
Applying the formulas above :-
For parallel connection :-
According to question, 4 such parallel connections are again connected in series.
Therefore, the total resistance = 4 + 4 + 4 + 4
⇒Total resistance = 16 Ω
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Verified answer
Given :-
Four resistors of 16 Ω each are connected in parallel, and another four resistors of 16 Ω each are connected in series.
To determine :-
The total resistance.
Acknowledgement :-
For connection in series,
For connection in parallel,
Solution :-
Applying the formulas above :-
For parallel connection :-
According to question, 4 such parallel connections are again connected in series.
Therefore, the total resistance = 4 + 4 + 4 + 4
⇒Total resistance = 16 Ω
Therefore, the total resistance is 16 Ω.