Verified answer

[tex]\huge\mathfrak\red{꧁☟︎︎︎answer✍︎꧂}[/tex]

Radius of the cylindrical part as well as the conical part =☟︎︎︎☟︎︎︎☟︎︎︎☟︎︎︎☟︎︎︎☟︎︎︎☟︎︎︎☟︎︎︎☟︎︎︎☟︎︎︎☟︎︎︎☟︎︎︎☟︎︎︎☟︎︎︎☟︎︎︎☟︎︎︎☟︎︎

[tex] r = \frac{diameter}{2} [/tex]

height of the cylindrical part =h=2.1m

slant height of the conical part=/=2.8

Total area of the canvas used in the tent

=CSA of the cylindrical part +CSA of the conical part

=2πrh+πrl

=πr(2h+l)

[tex] = \frac{22}{7} \times 2 \times (2 \times 2.1 + 2.8) {m}^{2} \\ [/tex]

[tex] = \frac{22}{7} \times 2 \times 7m^{2} [/tex]

[tex] = 44 {m}^{2} [/tex]

[tex]the \: rate \: of \: canvas \: is \: r \: 350 \: per \: {m}^{2} [/tex]

[tex]cost \: of \: 44 {m}^{2} \: canvas = r(44 \times 350) \\ = r \: 15,400[/tex]

THUS,The area of the canvas used for making the tent is 44m^2 and the cost of canvas is r 15,400

[tex]\sf \colorbox{pink} {ANSWER BY ACHALMUCHHAL2}[/tex]

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