Answer:
answers are in bold text as shown in the solution below
Step-by-step explanation:
VI. 15)
sum of exterior angles of polygon = 360
m<1 + 92 + 63 + 52 + 88 = 360
m<1 = 295
C. (question on the left side)
let x = measure of angle (note that 2 missing angles are equal so x + x)
x + x + 60 + 80 + 90 = 360
2x = 130
x = 65
(question on the right side)
add all measures then equate to 360
5x + (6x+3) + (4x+7) + (7x-4) + (9x-18) = 360
31x -12 = 360
31x = 372
x = 12
m<1 = 5x = 5(12) = 60
m<2 = 6x+3 = 6(12) + 3 = 75
m<3 = 4x+7 = 4(12) + 7 = 55
m<4 = 7x-4 = 7(12) - 4 = 80
m<5 = 9x-18 = 9(12) - 18 = 90
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Answers & Comments
Answer:
answers are in bold text as shown in the solution below
Step-by-step explanation:
VI. 15)
sum of exterior angles of polygon = 360
m<1 + 92 + 63 + 52 + 88 = 360
m<1 = 295
C. (question on the left side)
let x = measure of angle (note that 2 missing angles are equal so x + x)
x + x + 60 + 80 + 90 = 360
2x = 130
x = 65
(question on the right side)
add all measures then equate to 360
5x + (6x+3) + (4x+7) + (7x-4) + (9x-18) = 360
31x -12 = 360
31x = 372
x = 12
m<1 = 5x = 5(12) = 60
m<2 = 6x+3 = 6(12) + 3 = 75
m<3 = 4x+7 = 4(12) + 7 = 55
m<4 = 7x-4 = 7(12) - 4 = 80
m<5 = 9x-18 = 9(12) - 18 = 90