Please answer this question step by step for 50 points. Click on the image to view the question. Correct answer is C but explain the answer.
Answers & Comments
PrashantRaj8
First of all name all the resistors R1,R2,R3,R4,R5,R6,R7 and then keep those resistors which are joined by wire in parallel and calculate the resistance of first three resistor 1/R=1/R1+1/R2+1/R3 1/R=3/R R=R/3 nd now the last thre resistors in parallel R=R/3 then join the middle resistor R4 and both the equivalent resistance R/3 and R/3 in series then R eq.= R/3+R/3+R R=5R/3 this is the answer if u r satisfied then mark it as the brainliest thank you
Answers & Comments
R1,R2,R3,R4,R5,R6,R7
and then keep those resistors which are joined by wire in parallel and calculate the resistance of first three resistor
1/R=1/R1+1/R2+1/R3
1/R=3/R
R=R/3
nd now the last thre resistors in parallel
R=R/3
then join the middle resistor R4 and both the equivalent resistance R/3 and R/3 in series then
R eq.= R/3+R/3+R
R=5R/3
this is the answer
if u r satisfied then mark it as the brainliest
thank you
Here is your answer in the attachment