Answer:
this is your answer
please mark on brainliest
Step-by-step explanation:
=> take log both side
=> log( {x}^{log_{a}(y) } ) = log( {y}^{ log_{a}(x) } )
=> logay * logx = logax*logy
=> (logy/loga)*logx = (logx/loga)*logy
=> logy*logx = logx*logy
by equation we can write that when x=1 (log1=0),value of y could be anything.
OR
when y=1 value of x can be anything.
=> x=1. => y = any positive number.
=> y =1 => x = any +ve number.
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Answers & Comments
Answer:
this is your answer
please mark on brainliest
Step-by-step explanation:
=> take log both side
=> log( {x}^{log_{a}(y) } ) = log( {y}^{ log_{a}(x) } )
=> logay * logx = logax*logy
=> (logy/loga)*logx = (logx/loga)*logy
=> logy*logx = logx*logy
by equation we can write that when x=1 (log1=0),value of y could be anything.
OR
when y=1 value of x can be anything.
=> x=1. => y = any positive number.
OR
=> y =1 => x = any +ve number.