Answer:
2y - 3 = 7
where y = 5
Step-by-step explanation:
2y - 3 = 7 (0,3,5,7)
let us assume y = 0
2 × 0 - 3 ≠ 7
let us assume y = 3
2 × 3 - 3 ≠ 7
let us assume y = 5
2 × 5 - 3 = 7
let us assume y = 7
2 × 7 - 3 ≠ 7
therefore, y = 5
put 5 instead of y,
the equation will be,
2*5-3=7
10-3=7
7=7
that is true,
hence, y=5
to show that other options are incorrect,
put the other values instead of y in the equation.
if LHS ≠ RHS
the it is not the answer
but here 5 is satisfying LHS=RHS,
so 5 is the answer.
it was long, so please mark it the brainliest
Thank you.
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Answers & Comments
Answer:
2y - 3 = 7
where y = 5
Step-by-step explanation:
2y - 3 = 7 (0,3,5,7)
let us assume y = 0
2 × 0 - 3 ≠ 7
let us assume y = 3
2 × 3 - 3 ≠ 7
let us assume y = 5
2 × 5 - 3 = 7
let us assume y = 7
2 × 7 - 3 ≠ 7
therefore, y = 5
Answer:
put 5 instead of y,
the equation will be,
2*5-3=7
10-3=7
7=7
that is true,
hence, y=5
Step-by-step explanation:
to show that other options are incorrect,
put the other values instead of y in the equation.
if LHS ≠ RHS
the it is not the answer
but here 5 is satisfying LHS=RHS,
so 5 is the answer.
it was long, so please mark it the brainliest
Thank you.