Answer:
1. 4a2+4ab+b2
2. a2-4ab+4b2
3. a2+1+1/4a2
4. 4a2+4+1/a
5. a2+b2+c2+2ab-2bc-2ac
6. a2+b2+c2-2ab-2bc+2ac
7. +1 sq
8. -1 sq
(i) (2a+b)² = 4a²+4ab+b²
(ii) (a-2b)²= a²-4ab+4b²
(iii)(a+1/2a)²=a²+2×a×1/2a+1/4a²
=a²+1+4a²
(iv)(2a-1/a)²=4a²-2×2a×1/a+1/a²
=4a²-4+1/a²
(v)(a+b-c)²={a+(b-c)}²
={a²+2a(b-c)+(b-c)²}
=(a²+2ab-2ac+b²-2bc+c²)
(vi)(a-b+c)²={(a-b)+c}²
={(a-b)²+2(a-b)c+c²}
=(a²-2ab+b²+2ac-2bc+c²)
(vii)(3x+1/3x)²=(9x²+2×3x×1/3x+1/9x²)
=(9x²+2+1/9x²)
(viii)(2x-1/2x)²=(4x²-2×2x×1/2x+1/4x²)
=(4x²-2+1/4x²)
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Answers & Comments
Answer:
1. 4a2+4ab+b2
2. a2-4ab+4b2
3. a2+1+1/4a2
4. 4a2+4+1/a
5. a2+b2+c2+2ab-2bc-2ac
6. a2+b2+c2-2ab-2bc+2ac
7. +1 sq
8. -1 sq
Answer:
(i) (2a+b)² = 4a²+4ab+b²
(ii) (a-2b)²= a²-4ab+4b²
(iii)(a+1/2a)²=a²+2×a×1/2a+1/4a²
=a²+1+4a²
(iv)(2a-1/a)²=4a²-2×2a×1/a+1/a²
=4a²-4+1/a²
(v)(a+b-c)²={a+(b-c)}²
={a²+2a(b-c)+(b-c)²}
=(a²+2ab-2ac+b²-2bc+c²)
(vi)(a-b+c)²={(a-b)+c}²
={(a-b)²+2(a-b)c+c²}
=(a²-2ab+b²+2ac-2bc+c²)
(vii)(3x+1/3x)²=(9x²+2×3x×1/3x+1/9x²)
=(9x²+2+1/9x²)
(viii)(2x-1/2x)²=(4x²-2×2x×1/2x+1/4x²)
=(4x²-2+1/4x²)