In the figure, since angle 1 and 4 are supplementary, their sum must be 180. but in question, it's 50 and 40 which adds up to 90. Hence the question, according to the figure, is wrong.
In the figure, since angle 1 and 4 are supplementary, their sum must be 180. but in question, it's 50 and 40 which adds up to 90. Hence the question, according to the figure, is wrong.
Answers & Comments
Verified answer
1.
Two angles of ∆ are 50 and 50.
Third angle = 180 - (50+50) = 80°
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2.Difference between complementary angles = 60
Sum of complementary angles = 90
Smaller angle = (sum - difference)/2 = (90-60)/2 = 15°
Larger angle = (sum + difference)/2 = (90+60)/2 = 75°
Angles are 15° and 75°.
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3.
Difference between supplementary angles = 80
Sum of supplementary angles = 180
Smaller angle = (sum - difference)/2 = (180-80)/2 = 50°
Larger angle = (sum + difference)/2 = (180+80)/2 = 130°
Angles are 50° and 130°.
_____________________
4.
In the figure, since angle 1 and 4 are supplementary, their sum must be 180. but in question, it's 50 and 40 which adds up to 90. Hence the question, according to the figure, is wrong.
Answer:
1.
Two angles of ∆ are 50 and 50.
Third angle = 180 - (50+50) = 80°
___________________
2.Difference between complementary angles = 60
Sum of complementary angles = 90
Smaller angle = (sum - difference)/2 = (90-60)/2 = 15°
Larger angle = (sum + difference)/2 = (90+60)/2 = 75°
Angles are 15° and 75°.
________________________
3.
Difference between supplementary angles = 80
Sum of supplementary angles = 180
Smaller angle = (sum - difference)/2 = (180-80)/2 = 50°
Larger angle = (sum + difference)/2 = (180+80)/2 = 130°
Angles are 50° and 130°.
_____________________
4.
In the figure, since angle 1 and 4 are supplementary, their sum must be 180. but in question, it's 50 and 40 which adds up to 90. Hence the question, according to the figure, is wrong.