Given, θ = 120°
Area of sector
[tex] = (\frac{θ}{360°}) \times \pi {r}^{2} \\ = \frac{120}{360} \times \frac{22}{7} \times 21 \times 21 \\ = \frac{1}{3} \times 22 \times 3 \times 21 \\ = 1 \times 22 \times 21 \\ = 462 {cm}^{2} [/tex]
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Given, θ = 120°
Area of sector
[tex] = (\frac{θ}{360°}) \times \pi {r}^{2} \\ = \frac{120}{360} \times \frac{22}{7} \times 21 \times 21 \\ = \frac{1}{3} \times 22 \times 3 \times 21 \\ = 1 \times 22 \times 21 \\ = 462 {cm}^{2} [/tex]