Given,

AB = BC

I)

• AD is common in both the triangles
• ADB = ADC ( altitude AD is perpendicular on BC )
• BD = DC ( AD bisects BC )

II)

triangle ADB is congruent to triangle ADC by sas congruency ( side-angle-side )

III )

yes angle B = angle C since both the triangles are congruent and share one equal side

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