Answer:
9 . (a) In ∆PQR and ∆PSR
PQ = PS (given)
Angle 1 = Angle 2 ( given )
PR = PR ( common side )
Therefore, ∆PQR congruent to ∆PSR ( by SAS Congruency )
(b) QR = SR [ by CPCT { corresponding parts of congruent triangles }
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Answer:
9 . (a) In ∆PQR and ∆PSR
PQ = PS (given)
Angle 1 = Angle 2 ( given )
PR = PR ( common side )
Therefore, ∆PQR congruent to ∆PSR ( by SAS Congruency )
(b) QR = SR [ by CPCT { corresponding parts of congruent triangles }