Answer:

Let Gautam's Diwali bonus be x.

Gautam gave 1/3 of his bonus to his son, so he gave (1/3)x to his son.

Gautam gave 1/2 of his bonus to his daughter, so he gave (1/2)x to his daughter.

The remaining amount that Gautam gave to his wife is equal to his bonus minus the amount he gave to his son and daughter. Therefore:

x - [(1/3)x + (1/2)x] = ₹15000

Multiplying through by 6, we get:

6x - 2x - 3x = ₹90000

Simplifying, we get:

x = ₹30000

Therefore, Gautam received ₹30000 as his Diwali bonus.

Verified answer

Answer:

To do this very very tough question you need common sense.

Step-by-step explanation:

let the amount of diwali bonus be x

He gave 1/3 part of bonus that is x/3

he gave 1/2 part of bonus that is x/2

So remaining part that he gave to her wife will be x - [ x/2+x/3]

we will open bracket so this would be

x-x/2-x/3

taking common factor we get

x - 3x-2x/6

= x - x/6

= 6x-x/6

= 5x/6. ............. Amount given to wife. (1)

According to given condition

Amount given to wife = 15000

5x/6 = 15000 from eqn 1

5x=90000

x= 18000 rupees

Therefore Gautam receives 18,000 rupees as his diwali bonus.