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Rishika1802
@Rishika1802
October 2021
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please answer the following question1
Answers & Comments
yuvrajkj
Given,
initial velocity, u = (3i+4j)
acceleration, a = (0.4i + 0.3j)
time for which speed is calculated, t = 10 sec
applying law of motion
v= u + at
=> v = 3i + 4 j + (0.4i + 0.3j) x 10
=> v = 7i + 7j
This is the velocity after 10 sec. But as we know,
MAGNITUDE OF VELOCITY AT ANY TIME = SPEED AT THAT TIME.
so magnitude of speed = ✓(7i^2 + 7j^2)
=> ✓(49+49)
=> 7✓2 units.
Happy to help.
0 votes
Thanks 1
yuvrajkj
agar meri maano to go for cengage series
yuvrajkj
or dc pandey
Rishika1802
ha apne btaya tha i'll buy that soon
Rishika1802
actually mere area me vo available nhi ha
yuvrajkj
hmm
yuvrajkj
All the best
Rishika1802
ty and same to you
yuvrajkj
Let me know if any in any way i can help
yuvrajkj
in any*
Rishika1802
ya ill ask whenever i ll need ur help
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Answers & Comments
initial velocity, u = (3i+4j)
acceleration, a = (0.4i + 0.3j)
time for which speed is calculated, t = 10 sec
applying law of motion
v= u + at
=> v = 3i + 4 j + (0.4i + 0.3j) x 10
=> v = 7i + 7j
This is the velocity after 10 sec. But as we know,
MAGNITUDE OF VELOCITY AT ANY TIME = SPEED AT THAT TIME.
so magnitude of speed = ✓(7i^2 + 7j^2)
=> ✓(49+49)
=> 7✓2 units.
Happy to help.