a. The phenotype of F1 progeny would be "Axial Round" because the F1 generation is a result of crossing the axial (AARR) parent with the round (aarr) parent. The dominant traits for flower position (axial) and seed shape (round) will be expressed in the F1 generation.
b. The phenotypes of F2 progeny produced by self-pollination of F1 progeny will be:
Axial Round (AARR)
Axial Wrinkled (AaRr)
Terminal Round (AARR)
Terminal Wrinkled (AaRr)
c. The phenotypic ratio of F2 progeny will be:
1:2:1
This is the phenotypic ratio resulting from the cross between heterozygous individuals (AaRr x AaRr). The ratio indicates that there will be 1 dominant phenotype (Axial Round), 2 different combinations of heterozygous phenotypes (Axial Wrinkled and Terminal Round), and 1 recessive phenotype (Terminal Wrinkled) in the F2 generation.
Answers & Comments
Answer:
a. The phenotype of F1 progeny would be "Axial Round" because the F1 generation is a result of crossing the axial (AARR) parent with the round (aarr) parent. The dominant traits for flower position (axial) and seed shape (round) will be expressed in the F1 generation.
b. The phenotypes of F2 progeny produced by self-pollination of F1 progeny will be:
Axial Round (AARR)
Axial Wrinkled (AaRr)
Terminal Round (AARR)
Terminal Wrinkled (AaRr)
c. The phenotypic ratio of F2 progeny will be:
1:2:1
This is the phenotypic ratio resulting from the cross between heterozygous individuals (AaRr x AaRr). The ratio indicates that there will be 1 dominant phenotype (Axial Round), 2 different combinations of heterozygous phenotypes (Axial Wrinkled and Terminal Round), and 1 recessive phenotype (Terminal Wrinkled) in the F2 generation.