Answer:
Correct option is C)
Using work energy theorem
Work done by friction=K.E + P.E.
∴0.5×mgd=21m(2gr)2+mg×2r
0.5×mgd=mgr+2mgr
0.5×mgd=3mgrd=6×r=6m
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Answer:
Correct option is C)
Using work energy theorem
Work done by friction=K.E + P.E.
∴0.5×mgd=21m(2gr)2+mg×2r
0.5×mgd=mgr+2mgr
0.5×mgd=3mgrd=6×r=6m