Answer:
1.) m<ABC = 80°
Solution:
Given: mADC = 160°
So: m<ABC = 1/2 mADC = 1/2×/60° = 80°
2.) m<MQL = 40°
1. Firstly, find the centre point
2. Second, connect point M and point L with O
3. Then: OMLQM, OL LQL
{Tangent theorem}
4. m<B + m<MQL = 180°
m<B = m ML/m MKL thenL 360° = 140/220+(40 × 360°
= 140/360 × 360°
= 140°
5. So: m<MQL = 180° - MLB
= 180° - 140°
= 40°
Step-by-step explanation:
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Answers & Comments
Answer:
1.) m<ABC = 80°
Solution:
Given: mADC = 160°
So: m<ABC = 1/2 mADC = 1/2×/60° = 80°
2.) m<MQL = 40°
1. Firstly, find the centre point
2. Second, connect point M and point L with O
3. Then: OMLQM, OL LQL
{Tangent theorem}
4. m<B + m<MQL = 180°
m<B = m ML/m MKL thenL 360° = 140/220+(40 × 360°
= 140/360 × 360°
= 140°
5. So: m<MQL = 180° - MLB
= 180° - 140°
= 40°
Step-by-step explanation:
Nawa PO NAKATULONG PO AKO PA BRAINLIEST NA RIN PO! :))