Answer:

these are the answers for both the questions

Step-by-step explanation:

(i)(2y-5)²

=( a-b)²

=a²-2ab+b²

=(2y)²-2*2y*5+5²

=4y²-20y+25

(ii)(2a+7)²

= (a+b)²

=a²+2ab+b²

=2a²+2*2a*7+7²

=4a²+28a+49

done! all the best for your exams