Answer:
Three consecutive odd natural numbers are such that the product of the first and third exceeds four times the middle by 1, then the numbers are 3,5 and 7.
3, 5 and 7.
Solution:
Let the three consecutive odd numbers be x , (x+2) and (x+4).
[tex]x \times (x + 4) - 4(x + 2)= 1 \\ {x}^{2} + 4x - 4x - 8 = 1 \\ {x}^{2} - 8= 1 \\ {x}^{2} = 1 + 8 \\ {x}^{2} = 9 \\ x = \sqrt{9} = 3 \\ numbers \: are : \\ x = 3 \\ (x + 2) = 3 + 2 = 5 \\ (x + 4) = 3 + 4 = 7[/tex]
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Answers & Comments
Answer:
Three consecutive odd natural numbers are such that the product of the first and third exceeds four times the middle by 1, then the numbers are 3,5 and 7.
Verified answer
Answer:
3, 5 and 7.
Solution:
Let the three consecutive odd numbers be x , (x+2) and (x+4).
[tex]x \times (x + 4) - 4(x + 2)= 1 \\ {x}^{2} + 4x - 4x - 8 = 1 \\ {x}^{2} - 8= 1 \\ {x}^{2} = 1 + 8 \\ {x}^{2} = 9 \\ x = \sqrt{9} = 3 \\ numbers \: are : \\ x = 3 \\ (x + 2) = 3 + 2 = 5 \\ (x + 4) = 3 + 4 = 7[/tex]