Answer:

(ii) x ^ 2 + 2ax + (a + b)(a - b we can factorize it as follows:

x ^ 2 + 2ax + (a + b)(a - b)

= x ^ 2 + 2ax + (a ^ 2 - b ^ 2)

= (x + a) ^ 2 - b ^ 2

This is a difference of squares which can be further factored as:

(x + a + b)(x + a - b)

So the factors for expression (ii) are: (x + a + b) and (x + a - b).

Answer:

[x + a + b) ] [ x + a - b ]

Step-by-step explanation:

x² + 2a x + (a+b)(a-b)

= x² + 2a x + (a² - b²)

= (x + a)² - b², it's in the form of p² - q²

= [(x + a) + b) ] [ (x + a) - b ]