Answer:
x²+2ax+(a+b)(a-b)
=x²+2ax+a²-b² since a²+b²=(a+b)(a-b)
=(x²+2ax+a²)-b²
=(a+x)²-b² since(a+b)²=a²+b²+2ab
=(a+x-b)(a+x+b)
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[tex]x^{2}+a^{2} - b^{2}[/tex]
Step-by-step explanation:
We know that [tex](a + b) (a - b) = a^{2} - b^{2}[/tex]
So, Now [tex]x^{2} + 2ax + a^{2} - b^{2}[/tex]We can further factorise x^2 +2ax + a^2By (a+b)^2 formula which is a ^2 + 2ab + b^2.
Then the answer will be [tex]x^{2}+a^{2} - b^{2}[/tex]
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Verified answer
Answer:
x²+2ax+(a+b)(a-b)
=x²+2ax+a²-b² since a²+b²=(a+b)(a-b)
=(x²+2ax+a²)-b²
=(a+x)²-b² since(a+b)²=a²+b²+2ab
=(a+x-b)(a+x+b)
IF IT HELPS YOU
PLEASE MARK AS BRAINLIST
Answer:
[tex]x^{2}+a^{2} - b^{2}[/tex]
Step-by-step explanation:
We know that [tex](a + b) (a - b) = a^{2} - b^{2}[/tex]
So, Now [tex]x^{2} + 2ax + a^{2} - b^{2}[/tex]
We can further factorise x^2 +2ax + a^2
By (a+b)^2 formula which is a ^2 + 2ab + b^2.
Then the answer will be [tex]x^{2}+a^{2} - b^{2}[/tex]