Answer:
1
Step-by-step explanation:
=
x
2
−5x+9
⇒yx
−(5y+1)x+9y=0
As x is real, discriminant ≥0
⇒(5y+1)
−36y
≥0
⇒11y
−10y−1≤0
∴y∈[−
11
,1]
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Answers & Comments
Answer:
1
Step-by-step explanation:
=
x
2
−5x+9
x
⇒yx
2
−(5y+1)x+9y=0
As x is real, discriminant ≥0
⇒(5y+1)
2
−36y
2
≥0
⇒11y
2
−10y−1≤0
∴y∈[−
11
1
,1]