aditya4062
Qpr=50 pq=pr(tangents of a circle) pqr=pqr(angle opp to equal sides are equal) now, in∆pqr qpr+pqr+prq=180(angle sum property of a ∆) 50+pqr+pqr=180 2pqr=180-50 2pqr=130 pqr=130/2 pqr=65 now, oqp=90(line drawn from the centre to the tangent is perpendicular) oqr=oqp-pqr oqr=90-65 oqr=25
Answers & Comments
pq=pr(tangents of a circle)
pqr=pqr(angle opp to equal sides are equal)
now,
in∆pqr
qpr+pqr+prq=180(angle sum property of a ∆)
50+pqr+pqr=180
2pqr=180-50
2pqr=130
pqr=130/2
pqr=65
now,
oqp=90(line drawn from the centre to the tangent is perpendicular)
oqr=oqp-pqr
oqr=90-65
oqr=25