perimeter of the field=2(100+75)=350m
5 times 350=5x350=1750meter=1.75 kms
time=0.25 hours
so, speed=
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perimeter of the field=2(100+75)=350m
5 times 350=5x350=1750meter=1.75 kms
time=0.25 hours
so, speed=![\frac{distance}{time} =\frac{1.75}{0.25} =7km/hr \frac{distance}{time} =\frac{1.75}{0.25} =7km/hr](https://tex.z-dn.net/?f=%5Cfrac%7Bdistance%7D%7Btime%7D%20%3D%5Cfrac%7B1.75%7D%7B0.25%7D%20%3D7km%2Fhr)
= 350 metres.
Now, Total distance covered in 5 rounds = 5×350 = 1750 metres.
=> s = 1750 metres...●
Time taken to cover this distance = A quarter = 15 minutes = 900 seconds.
=> t = 900 seconds...●
Thus,
Required Speed (v) = s / t
v = 1750 / 900
v = 1.944 m/s
Required Speed in km/h =>
v = 1.944 × 18 / 5
v = 34.999/5
v = 6.99 km/h......●
Thus, She should jog at the speed of 7 km/h approximately.
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Hope it was helpful.