1. Area of a rectangle = Length times width (l*w)
Area of this rectangle = 126sqft
Equation: (x) * (3 + 3x) = 126
W (width) = x
L (length) = 3 + 3x
(x) * (3x + 3) = 126
3x^2 + 3x = 126
3x^2 + 3x -126 = 126 - 126
3x^2 + 3x -126 = 0
3 (x - 6) (x + 7) = 0
x = 6 or x = -7
Choose x with a positive value, since measurements cannot be negative.
Replace Xs with 6:
(6) * (3(6) + 3) = 126
(6) * (18 + 3) = 126
(6) * (21) = 126
126 = 126
Therefore, the length of the tarpaulin is 21ft, while its width is 6ft.
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Answers & Comments
1. Area of a rectangle = Length times width (l*w)
Area of this rectangle = 126sqft
Equation: (x) * (3 + 3x) = 126
W (width) = x
L (length) = 3 + 3x
(x) * (3x + 3) = 126
3x^2 + 3x = 126
3x^2 + 3x -126 = 126 - 126
3x^2 + 3x -126 = 0
3 (x - 6) (x + 7) = 0
x = 6 or x = -7
Choose x with a positive value, since measurements cannot be negative.
Replace Xs with 6:
(x) * (3x + 3) = 126
(6) * (3(6) + 3) = 126
(6) * (18 + 3) = 126
(6) * (21) = 126
126 = 126
Therefore, the length of the tarpaulin is 21ft, while its width is 6ft.