First, we will be using the Ideal Gas Equation, PV = nRT, to find out the amount of substance, n. Take note that I converted the volume from milliliters to liters and the temperature from Celsius to Kelvin.
PV = nRT
n = PV / RT
n = (0.85)(0.68) / (0.0821)(301.15)
n = 0.023377701
That means that 0.023377701 moles of this gas weighs 2.6 grams. Now we can determine its molar mass, which is the weight of 1 mole of this gas.
Answers & Comments
First, we will be using the Ideal Gas Equation, PV = nRT, to find out the amount of substance, n. Take note that I converted the volume from milliliters to liters and the temperature from Celsius to Kelvin.
PV = nRT
n = PV / RT
n = (0.85)(0.68) / (0.0821)(301.15)
n = 0.023377701
That means that 0.023377701 moles of this gas weighs 2.6 grams. Now we can determine its molar mass, which is the weight of 1 mole of this gas.
(1/0.023377701)(2.6) = 111.2170953
The molar mass is 111.22 g/mol.