Answer:
The lenght of the rectangular lot is 9 cm and its width is 5 cm.
Step-by-step explanation:
In mathematics, area define as the amount of space can be occupied inside the flat surface or surface of solid.
How to Solve the Problem
Required two equation to solve two unknown variable (lenght and width)
Apply your knowledge in algebra, finding unknown variable
Use the formula A=lw
Equate two equation and solve for two unknown variable
Given
area is 45 sq. cm.
width (w)
length (3w-6)
Solution
1st equation is l= 3w - 6
2nd equation is 45= LW
Equate to solve for w
a= lw
45= (3w-6)w, then expand
45= 3w^2 - 6w
Simplify (divisible of 3)
1/3(45= 3w^2 - 6w)
15 = w^2 - 2w
w^2 - 2w - 15 = 0, in standard form
Use factoring to solve for w
w^2 - 2w - 15 = 0
(w-5)(w+3)= 0
w-5= 0, w= 5
w+3= 0, w= -3
Use the positive solution, there is no negative dimension
w= 5 cm
if l= 3w-6
l= 3(5)-6
l= 9 cm
Therefore, the length of the rectangular lot is 9 cm and its width is 5cm.
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Answers & Comments
Answer:
The lenght of the rectangular lot is 9 cm and its width is 5 cm.
Step-by-step explanation:
In mathematics, area define as the amount of space can be occupied inside the flat surface or surface of solid.
How to Solve the Problem
Required two equation to solve two unknown variable (lenght and width)
Apply your knowledge in algebra, finding unknown variable
Use the formula A=lw
Equate two equation and solve for two unknown variable
Given
area is 45 sq. cm.
width (w)
length (3w-6)
Solution
1st equation is l= 3w - 6
2nd equation is 45= LW
Equate to solve for w
a= lw
45= (3w-6)w, then expand
45= 3w^2 - 6w
Simplify (divisible of 3)
1/3(45= 3w^2 - 6w)
15 = w^2 - 2w
w^2 - 2w - 15 = 0, in standard form
Use factoring to solve for w
w^2 - 2w - 15 = 0
(w-5)(w+3)= 0
w-5= 0, w= 5
w+3= 0, w= -3
Use the positive solution, there is no negative dimension
w= 5 cm
if l= 3w-6
l= 3(5)-6
l= 9 cm
Therefore, the length of the rectangular lot is 9 cm and its width is 5cm.