The pilot will observe the path of bomb in the shape of a parabola.
EXPLANATION:
The velocity with which the plane is moving along is horizontal and constant. The velocity of the pilot and the plane are taken equivalent. The path of bomb falling will move directly below the plane, making the x-coordinate; x = ut and the y axis of the falling bomb is taken as therefore, the path equation of the bomb is now as we can seethe equation as
Therefore, by the equation path of the bomb drop we can say that the pilot will see the path of bomb drop as parabola.
Answers & Comments
Answer:
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ANSWER:
The pilot will observe the path of bomb in the shape of a parabola.
EXPLANATION:
The velocity with which the plane is moving along is horizontal and constant. The velocity of the pilot and the plane are taken equivalent. The path of bomb falling will move directly below the plane, making the x-coordinate; x = ut and the y axis of the falling bomb is taken as
therefore, the path equation of the bomb is
now as we can seethe equation as ![y=k x^{2} y=k x^{2}](https://tex.z-dn.net/?f=y%3Dk%20x%5E%7B2%7D)
Therefore, by the equation path of the bomb drop we can say that the pilot will see the path of bomb drop as parabola.