Given two pts (-1, 2) (4, 7)
m = (y2 - y1) / (x2 -x1)
m = ( 7 - 2) / (4 - (-1)
m = 5 / 5
m = 1
y = mx + b
7 = 1(4) + b
b = 7 - 4
b = 3
y = 1x + 3
1x - y = - 3
The equation of the line in the form Ax + By = C is 1x - y = - 3
Given two pts (5, -8) (0, 0)
m = ( 0 - (-8) / (0 - 5)
m = 8 / -5
0 = - 8/5(0) + b
b = 0
y = -8/5x + 0
y = - 8/5x
-8/5x - y = 0
8/5x + y = 0
The equation of the line in the form Ax + By = C is 8/5x + y = 0
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Answers & Comments
Problem 1:
Given two pts (-1, 2) (4, 7)
m = (y2 - y1) / (x2 -x1)
m = ( 7 - 2) / (4 - (-1)
m = 5 / 5
m = 1
y = mx + b
7 = 1(4) + b
b = 7 - 4
b = 3
y = mx + b
y = 1x + 3
1x - y = - 3
Answer:
The equation of the line in the form Ax + By = C is 1x - y = - 3
Problem 2:
Given two pts (5, -8) (0, 0)
m = (y2 - y1) / (x2 -x1)
m = ( 0 - (-8) / (0 - 5)
m = 8 / -5
y = mx + b
0 = - 8/5(0) + b
b = 0
y = mx + b
y = -8/5x + 0
y = - 8/5x
-8/5x - y = 0
8/5x + y = 0
Answer:
The equation of the line in the form Ax + By = C is 8/5x + y = 0
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