Answer:
1. A. The probability of picking a 7 after picking one card.
B. 5 cards numbered 1,3,5,7 and 9
C. Division (÷)
D. P(A)= 1÷5 (Number of favourable events ÷ number of total events)
E. 1 ÷ 5= 0.2 (The probability of picking a 7 after picking one card is 1/5 or 0.2)
2. A. The probability of selecting an A when choosing a letter in the word MATH.
B. 4 letter word "MATH"
D. P(A)= 1÷4 (Number of favourable events ÷ number of total events)
E. 1÷4 = 0.25 ( The probability of selecting an A when choosing a letter in the word MATH is 1/4 or 0.25)
3. A. The probability of a boy winning a five contenstant spelling contest.
B. Five boys
D. P(A) = 1÷5 (Number of favourable events ÷ number of total events)
E. 1÷5 = 0.2 ( The probability of a boy winning a five contenstant spelling contest is 1/5 or 0.20)
4. A. The probability of a boy being choosen as a cheerleader.
B. 20 boys and 20 girls
D. P(A) = 20÷40 (Number of favourable events ÷ number of total events)
E. 20÷40 = 0.5 ( The probability of a boy being choosen as a cheerleader is 1/2 or 0.5)
5. A. The probability of an even number of dots showing up when the dice is rolled.
B. even number of dots
D. P(A) = 3÷6 (Number of favourable events ÷ number of total events)
E. 3÷6 = 0.5 (The probability of an even number of dots showing up when the dice is rolled is 1/2 or 0.5)
Explanation
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Answers & Comments
Answer:
1. A. The probability of picking a 7 after picking one card.
B. 5 cards numbered 1,3,5,7 and 9
C. Division (÷)
D. P(A)= 1÷5 (Number of favourable events ÷ number of total events)
E. 1 ÷ 5= 0.2 (The probability of picking a 7 after picking one card is 1/5 or 0.2)
2. A. The probability of selecting an A when choosing a letter in the word MATH.
B. 4 letter word "MATH"
C. Division (÷)
D. P(A)= 1÷4 (Number of favourable events ÷ number of total events)
E. 1÷4 = 0.25 ( The probability of selecting an A when choosing a letter in the word MATH is 1/4 or 0.25)
3. A. The probability of a boy winning a five contenstant spelling contest.
B. Five boys
C. Division (÷)
D. P(A) = 1÷5 (Number of favourable events ÷ number of total events)
E. 1÷5 = 0.2 ( The probability of a boy winning a five contenstant spelling contest is 1/5 or 0.20)
4. A. The probability of a boy being choosen as a cheerleader.
B. 20 boys and 20 girls
C. Division (÷)
D. P(A) = 20÷40 (Number of favourable events ÷ number of total events)
E. 20÷40 = 0.5 ( The probability of a boy being choosen as a cheerleader is 1/2 or 0.5)
5. A. The probability of an even number of dots showing up when the dice is rolled.
B. even number of dots
C. Division (÷)
D. P(A) = 3÷6 (Number of favourable events ÷ number of total events)
E. 3÷6 = 0.5 (The probability of an even number of dots showing up when the dice is rolled is 1/2 or 0.5)
Explanation
Thank me later, haba ng tanong mo e joke hehe ^_^