Answer:
Solution On No. 1:
The initial statement is and .
To convert to an equation multiply by k the constant of variation:
⇒
To find "k" use the given conditions:
when
equation is
when then,
Final Answer On #1:
Solution On No. 2:
First find the constant variation which is k
k = ,
k = 15 divide 3
k = 5, so our constant variation is 5
Go to the next given
y = kx
y = 5 x 12 , kase k = 5 and x = 12
5 x 12 = 60
y = 60.
Final Answer On #2:
Solution On No. 4:
DIRECT VARIATION
6=K(1/3)
K=18
Y=(18)(10)
Y=180
IF INVERSE VARIATION
6=K/(1/3)
K=2
Y=2/10
Y=1/5
Final Answer On #4:
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#CarryOnLearning
#ProvideGreatAnswer
#Don'tAnswerNonsense
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Answers & Comments
Answer:
Solution On No. 1:
The initial statement is
and
.
To convert to an equation multiply by k the constant of variation:
⇒![y = kx y = kx](https://tex.z-dn.net/?f=y%20%3D%20kx)
To find "k" use the given conditions:
equation is![\red{\boxed{y = \frac{3}{2} x} \red{\boxed{y = \frac{3}{2} x}](https://tex.z-dn.net/?f=%5Cred%7B%5Cboxed%7By%20%3D%20%5Cfrac%7B3%7D%7B2%7D%20x%7D)
when
then,
Final Answer On #1:
Solution On No. 2:
First find the constant variation which is k
k =
,
k =
15 divide 3
k = 5, so our constant variation is 5
Go to the next given
y = kx
y = 5 x 12 , kase k = 5 and x = 12
5 x 12 = 60
y = 60.
Final Answer On #2:
Solution On No. 4:
DIRECT VARIATION
6=K(1/3)
K=18
Y=(18)(10)
Y=180
IF INVERSE VARIATION
6=K/(1/3)
K=2
Y=2/10
Y=1/5
Final Answer On #4:
Hashtags:
#CarryOnLearning
#ProvideGreatAnswer
#Don'tAnswerNonsense