Answer:
Step-by-step explanation:
1) CD =13 = DV = ID = DO diagonals theorem of a rectangle
DV = 13
2) IO = ID + DO = 13 + 13 = 26
3) m∠FEA = 38°
so m∠CEA = 38° The diagonals of a rhombus intersect at equal angles.
4) m∠EFS = ?
angles of triangle EFS:
180 = m∠FES + m∠EFS + 90° Diagonals bisect each other perpendicularly
m∠EFS = 180 - m∠FES -90 = 180 - 38 -90 = 52°
5)∠AYS = 90° In a square, the diagonals bisect each other so 90°
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Answer:
Step-by-step explanation:
1) CD =13 = DV = ID = DO diagonals theorem of a rectangle
DV = 13
2) IO = ID + DO = 13 + 13 = 26
3) m∠FEA = 38°
so m∠CEA = 38° The diagonals of a rhombus intersect at equal angles.
4) m∠EFS = ?
angles of triangle EFS:
180 = m∠FES + m∠EFS + 90° Diagonals bisect each other perpendicularly
m∠EFS = 180 - m∠FES -90 = 180 - 38 -90 = 52°
5)∠AYS = 90° In a square, the diagonals bisect each other so 90°