*Please read and understand my solution. Don't just rely on my direct answer*
Let x be multiplied to each part of the ratio having a sum of 459. Find the value of x.
The value of x is 51. Now multiply the value of x to each part of the ratio.
Therefore, the partition of 459 in the ratio of 2:4:3 is 102:204:153
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neilmarisidro2520
Hi, magandang gabi! Maaari mo ba akong tulungan sa aking tanong sa Math? Paumanhin sa abala.
Narito ang link sa aking tanong:
hi! ace, genius and moderators! kindly help me in my Math? please don't waste my points, answer it correctly! thanks! sa... https://brainly.ph/question/26402870?utm_source=android&utm_medium=share&utm_campaign=question
Note: Please answer my question correctly, nonsense answer will be reported.
neilmarisidro2520
Hi, magandang gabi! Maaari mo ba akong tulungan sa aking tanong sa Math? Paumanhin sa abala.
Narito ang link sa aking tanong:
hi! ace, genius and moderators! kindly help me in my Math? please don't waste my points, answer it correctly! thanks! sa... https://brainly.ph/question/26402848?utm_source=android&utm_medium=share&utm_campaign=question
Note: Please answer my question correctly, nonsense answer will be reported.
neilmarisidro2520
Magandang umaga po! Paumanhin po sa abala, pwede po ba ninyo sagutan ang aking katanungan subject Math at na ask ko na po please po sana masagutan mo po, maraming salamat po! :)
Jasriel78
Math-8 be nice po. Thankyou. https://brainly.ph/question/26407853?utm_source=android&utm_medium=share&utm_campaign=question
Answers & Comments
Verified answer
✒️RATIO
*Please read and understand my solution. Don't just rely on my direct answer*
Let x be multiplied to each part of the ratio having a sum of 459. Find the value of x.
The value of x is 51. Now multiply the value of x to each part of the ratio.
Therefore, the partition of 459 in the ratio of 2:4:3 is 102 : 204 : 153
(ノ^_^)ノ![\large\qquad\qquad\qquad\tt 3/ 15/2022 \large\qquad\qquad\qquad\tt 3/ 15/2022](https://tex.z-dn.net/?f=%20%5Clarge%5Cqquad%5Cqquad%5Cqquad%5Ctt%20%203%2F%2015%2F2022%20)
Narito ang link sa aking tanong:
hi! ace, genius and moderators! kindly help me in my Math? please don't waste my points, answer it correctly! thanks! sa...
https://brainly.ph/question/26402870?utm_source=android&utm_medium=share&utm_campaign=question
Note: Please answer my question correctly, nonsense answer will be reported.
Narito ang link sa aking tanong:
hi! ace, genius and moderators! kindly help me in my Math? please don't waste my points, answer it correctly! thanks! sa...
https://brainly.ph/question/26402848?utm_source=android&utm_medium=share&utm_campaign=question
Note: Please answer my question correctly, nonsense answer will be reported.
be nice po.
Thankyou.
https://brainly.ph/question/26407853?utm_source=android&utm_medium=share&utm_campaign=question