Verified answer

Answer:

Explanation:

Initial velocity of the ball        u=100 m/s

Acceleration of the ball        a=−g=−10  m/s

2

Using          v=u+at

∴     v=100−10t

Thus v−t graph is a straight line intersecting the t axis at  t=10 s

Also       v

∣

∣

∣

∣

∣

​

t=15

​

=100−10(15)=−50    m/s

2

Height (displacement) of the ball is equal to the area under the curve during   0<t<15

∴    h=

2

1

​

×100×10−

2

1

​

×(15−10)×50=375  m