Answer:
Step-by-step explanation:
1. Formula: s = d/t
Given: t = 3 hours
d = 192 km
Solve: s = d/t
s = 192km/3hrs
s = 64km/hr
2. d = 15 miles
t = 2hours and 30 minutes or 2.5 hours
Asked: speed in mph
Solve:
s = d/t
s = 15mi/2.5hrs
s = 4.21mi/hr
3. s = 5km/hr
t = 2hours
Solve
d = st
d = 5km/hr(2hrs)
d = 10km
4. s = 30mi/hr
d = 70mi
t = d/s
t = 70mi/30mi/hr
t = 2.33 hours
5. s = 54km/hr
s = 45km/hr
Let x be the number of minutes that the bus is moving
y be the number of minutes that the bus is stopping
Everything considers a 1 hour period.
When the bus stops, speed is zero.
Time considered here is minutes.
54x + 0y = 45(60mins)
54x = 2700
x = 2700/54
x = 50mins
Get the value of y
x + y = 60 mins
50mins + y = 60mins
y = 60mins - 50mins
y = 10 mins
The bus stops for 10 mins each hour.
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Verified answer
Answer:
Step-by-step explanation:
1. Formula: s = d/t
Given: t = 3 hours
d = 192 km
Solve: s = d/t
s = 192km/3hrs
s = 64km/hr
2. d = 15 miles
t = 2hours and 30 minutes or 2.5 hours
Asked: speed in mph
Solve:
s = d/t
s = 15mi/2.5hrs
s = 4.21mi/hr
3. s = 5km/hr
t = 2hours
Solve
d = st
d = 5km/hr(2hrs)
d = 10km
4. s = 30mi/hr
d = 70mi
t = d/s
t = 70mi/30mi/hr
t = 2.33 hours
5. s = 54km/hr
s = 45km/hr
Let x be the number of minutes that the bus is moving
y be the number of minutes that the bus is stopping
Everything considers a 1 hour period.
When the bus stops, speed is zero.
Time considered here is minutes.
54x + 0y = 45(60mins)
54x = 2700
x = 2700/54
x = 50mins
Get the value of y
x + y = 60 mins
50mins + y = 60mins
y = 60mins - 50mins
y = 10 mins
The bus stops for 10 mins each hour.
2. 115 mph
3. 10 km
4. 2 hours and 16 minutes
5. 10 minutes
Hope it helps:)