Answer:
p' (x) = 6x² + 2x –5
Explanation:
p (x) = 2x³ + x² –5x + k
take the derivative of both sides*
p' (x) d/dx ( 2x³ + x² –5x + k )
use differentiation rule*
*( d/dx (f+g) = d/dx (f) + d/dx (g) )*
p' (x) = d/dx (2x³) + d/dx (x²) + d/dx (–5x) +
d/dx (k)
calculate the derivative*
p' (x) = d/dx (2x³)+ d/dx (x²) + d/dx (–5x) +
d/dx (k).
2×3x²
d/dx (k
2x
–5
=0
so it's, p' (x) 2 × 3x² + 2x –5 + 0
p' (x) 2 × 3x² + 2x –5 + 0
simplify the expression of 2 × 3x² and +0
= 6x²
FINAL ANSWER:
sana makatulong <3
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Answers & Comments
Answer:
p' (x) = 6x² + 2x –5
Explanation:
p (x) = 2x³ + x² –5x + k
take the derivative of both sides*
p' (x) d/dx ( 2x³ + x² –5x + k )
use differentiation rule*
*( d/dx (f+g) = d/dx (f) + d/dx (g) )*
p' (x) = d/dx (2x³) + d/dx (x²) + d/dx (–5x) +
d/dx (k)
calculate the derivative*
p' (x) = d/dx (2x³)+ d/dx (x²) + d/dx (–5x) +
d/dx (k).
2×3x²
calculate the derivative*
p' (x) = d/dx (2x³)+ d/dx (x²) + d/dx (–5x) +
d/dx (k
2x
calculate the derivative*
p' (x) = d/dx (2x³)+ d/dx (x²) + d/dx (–5x) +
d/dx (k)
–5
calculate the derivative*
p' (x) = d/dx (2x³)+ d/dx (x²) + d/dx (–5x) +
d/dx (k)
=0
so it's, p' (x) 2 × 3x² + 2x –5 + 0
p' (x) 2 × 3x² + 2x –5 + 0
simplify the expression of 2 × 3x² and +0
= 6x²
FINAL ANSWER:
p' (x) = 6x² + 2x –5
sana makatulong <3