v = 60m/s
initial height = 210m
x = v(t)
t = x/v
y = (g)(t²)/2
y = (g)(x/v)²/2
y = (g)(x²)/(2)(v²)
y = (9.81)(x²/(2)(60²)
210 = 9.81(x²)/2(3600)
210 = 9.81(x²)/7200
210(7200) = 9.81x²
1,512,000/9.81 = x²
x = √154,128.44
x = 392.6m
h = g(t²)/2
2h = gt²
t = √(2h/g)
t = √2(210)/(9.81)
t = √(420/9.81)
t = √42.81
t = 6.54sec
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Answers & Comments
Problem 1:
Given:
v = 60m/s
initial height = 210m
Solution:
a.)
x = v(t)
t = x/v
y = (g)(t²)/2
y = (g)(x/v)²/2
y = (g)(x²)/(2)(v²)
y = (9.81)(x²/(2)(60²)
210 = 9.81(x²)/2(3600)
210 = 9.81(x²)/7200
210(7200) = 9.81x²
1,512,000/9.81 = x²
x = √154,128.44
x = 392.6m
b.)
h = g(t²)/2
2h = gt²
t = √(2h/g)
t = √2(210)/(9.81)
t = √(420/9.81)
t = √42.81
t = 6.54sec
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