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4..What is the cyclist's average velocity if his position changes from 30 m, North to 50 m, North during a 5 second time interval?
4..What is the cyclist's average velocity if his position changes from 30 m, North to 50 m, North during a 5 second time interval?
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Answer:
Given:
Initial position: 30 m, N
Final Position: 50 m, N
Time: 5 s
Formula:
velocity: displacement
time
displacement= 50 m - 30 m
= 20 m
Solving:
velocity= 20 m
5 s
velocity= 4 m/s, North
The cyclist's average velocity is 4 m/s, North
Explanation:
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