1. You are pushing a friend on a sled. You push with a force of 20 N. Your friend and the sled together have a mass of 60 kg. Ignoring friction, what is the acceleration of your friend on the sled?
The force acting on an object is given by
where:
F = force
m = mass
a = acceleration
Solving for a
F = ma
Therefore, the acceleration of your friend is 0.333 m/s².
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2. A student pedaling a bicycle applies a net force of 400 N. The mass of the rider and the bicycle is 25 kg. What is the acceleration of the bicycle and the rider?
We can answer this question by using Newton's second law, which states that the net force acting on an object is equal to the product between the mass of the object and its acceleration:
F = ma
where F is the force,
m is the mass,
a is the acceleration
In this problem, we have
m = 25 kg is the mass of the rider + bicycle
F = 400 N is the force
Solving for a, we find the acceleration:
The acceleration is 16 m/s^2
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3. How much force will a tennis racket need to exert on a tennis ball, with a mass of 0.67 kg, to make it
accelerate at a rate of 5,600 m/s2?
F = ma where F is the applied force, m is the mass of the object and a is the acceleration.
Given mass of 0.67 Kg and acceleration of 5600 then substituting these values in the equation we obtain
F = ma = 0.67\times 5600 = 3752 N\approx 3800 N
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4.Gravity accelerates any object falling at 9.8 m/s2. What is the force that will be applied to the ground if an 88 kg box falls from the top of a shelf to the ground?
Answers & Comments
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1. You are pushing a friend on a sled. You push with a force of 20 N. Your friend and the sled together have a mass of 60 kg. Ignoring friction, what is the acceleration of your friend on the sled?
The force acting on an object is given by
where:
F = force
m = mass
a = acceleration
Solving for a
F = ma
Therefore, the acceleration of your friend is 0.333 m/s².
ㅤ
_________________________________________________
2. A student pedaling a bicycle applies a net force of 400 N. The mass of the rider and the bicycle is 25 kg. What is the acceleration of the bicycle and the rider?
We can answer this question by using Newton's second law, which states that the net force acting on an object is equal to the product between the mass of the object and its acceleration:
F = ma
where F is the force,
m is the mass,
a is the acceleration
In this problem, we have
m = 25 kg is the mass of the rider + bicycle
F = 400 N is the force
Solving for a, we find the acceleration:
The acceleration is 16 m/s^2
ㅤ
_________________________________________________
3. How much force will a tennis racket need to exert on a tennis ball, with a mass of 0.67 kg, to make it
accelerate at a rate of 5,600 m/s2?
F = ma where F is the applied force, m is the mass of the object and a is the acceleration.
Given mass of 0.67 Kg and acceleration of 5600 then substituting these values in the equation we obtain
F = ma = 0.67\times 5600 = 3752 N\approx 3800 N
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4.Gravity accelerates any object falling at 9.8 m/s2. What is the force that will be applied to the ground if an 88 kg box falls from the top of a shelf to the ground?
We have the formula:
w = m * g
w = weight = ¿?
m = mass = 88 kg
g = gravity = 9,8 m/s
Replacing according formula:
w = 88 kg * 9,8 m/s
Resolving:
w = 862,4 N
The force is of the weight 862,4 Newtons.
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