Answer:
\begin{gathered} \frac{ \sqrt{x + 1} }{x + 1} = 2 \\ \sqrt{x + 1} =2 (x + 1) \\ \sqrt{x + 1} = 2x + 2 \\ { \sqrt{x + 1} }^{2} = {(2x + 2)}^{2} \\ x + 1 = 4 {x}^{2} + 8x + 4 \\ 4 {x}^{2} + 7x + 3 = 0 \\ (x + 1)(4x + 3) = 0 \\ \\ x + 1 = 0 \\ x = - 1 \\ \\ 4x + 3 = 0 \\ 4x = - 3 \\ \frac{4x}{4} = \frac{ - 3}{4} \\ x = - \frac{3}{4} \end{gathered}
x+1
=2
=2(x+1)
=2x+2
2
=(2x+2)
x+1=4x
+8x+4
4x
+7x+3=0
(x+1)(4x+3)=0
x+1=0
x=−1
4x+3=0
4x=−3
4
=
−3
x=−
3
Therefore the value of x is - 1 or - 3/4
Step-by-step explanation:
yan lang
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Answers & Comments
Answer:
\begin{gathered} \frac{ \sqrt{x + 1} }{x + 1} = 2 \\ \sqrt{x + 1} =2 (x + 1) \\ \sqrt{x + 1} = 2x + 2 \\ { \sqrt{x + 1} }^{2} = {(2x + 2)}^{2} \\ x + 1 = 4 {x}^{2} + 8x + 4 \\ 4 {x}^{2} + 7x + 3 = 0 \\ (x + 1)(4x + 3) = 0 \\ \\ x + 1 = 0 \\ x = - 1 \\ \\ 4x + 3 = 0 \\ 4x = - 3 \\ \frac{4x}{4} = \frac{ - 3}{4} \\ x = - \frac{3}{4} \end{gathered}
x+1
x+1
=2
x+1
=2(x+1)
x+1
=2x+2
x+1
2
=(2x+2)
2
x+1=4x
2
+8x+4
4x
2
+7x+3=0
(x+1)(4x+3)=0
x+1=0
x=−1
4x+3=0
4x=−3
4
4x
=
4
−3
x=−
4
3
Therefore the value of x is - 1 or - 3/4
Step-by-step explanation:
yan lang