Answer:
1. 1 grams C6H8O6 is equal to 0.005677814032513 mole.
2. molar mass of the C6H8O6, you need to consult the atomic weight of the C, H and O atoms that are in the periodic table: C is 12; H is 1; O is 16
(12x6)+(1x8)+(16x6)= 176g/mol
176 g = 1 mol
0,5 g = x mol 500mg= 0,5 grams
molar mass = mass÷ moles
176 = 0,5÷ x
x= 2,84 x 10⁻³ mol
2) To find the number of molecules present in those 2,84 x 10⁻³ mol we need to multiple the moles by the Avogadro's constant
No. of molecules = Avogadro's constant x n° of moles
No. of molecules = 6.022 x 10²³ x 2,84 x 10⁻³
= 1.71 x 10²¹ molecules of vit C.
3. 12.00 g C-12 = 1 mol C-12 atoms = 6.022 × 1023 atoms • The number of particles in 1 mole is called Avogadro's Number (6.0221421 x 1023).
Explanation:
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Answers & Comments
Answer:
1. 1 grams C6H8O6 is equal to 0.005677814032513 mole.
2. molar mass of the C6H8O6, you need to consult the atomic weight of the C, H and O atoms that are in the periodic table: C is 12; H is 1; O is 16
(12x6)+(1x8)+(16x6)= 176g/mol
176 g = 1 mol
0,5 g = x mol 500mg= 0,5 grams
molar mass = mass÷ moles
176 = 0,5÷ x
x= 2,84 x 10⁻³ mol
2) To find the number of molecules present in those 2,84 x 10⁻³ mol we need to multiple the moles by the Avogadro's constant
No. of molecules = Avogadro's constant x n° of moles
No. of molecules = 6.022 x 10²³ x 2,84 x 10⁻³
= 1.71 x 10²¹ molecules of vit C.
3. 12.00 g C-12 = 1 mol C-12 atoms = 6.022 × 1023 atoms • The number of particles in 1 mole is called Avogadro's Number (6.0221421 x 1023).
Explanation:
rosie_posie
Hope It Helps
pa brainliest po sana.
1. 1 grams C6H8O6 is equal to 0.005677814032513 mole.
2. molar mass of the C6H8O6, you need to consult the atomic weight of the C, H and O atoms that are in the periodic table: C is 12; H is 1; O is 16
(12x6)+(1x8)+(16x6)= 176g/mol
176 g = 1 mol
0,5 g = x mol 500mg= 0,5 grams
molar mass = mass÷ moles
176 = 0,5÷ x
x= 2,84 x 10⁻³ mol
2) To find the number of molecules present in those 2,84 x 10⁻³ mol we need to multiple the moles by the Avogadro's constant
No. of molecules = Avogadro's constant x n° of moles
No. of molecules = 6.022 x 10²³ x 2,84 x 10⁻³
= 1.71 x 10²¹ molecules of vit C.
3. 12.00 g C-12 = 1 mol C-12 atoms = 6.022 × 1023 atoms • The number of particles in 1 mole is called Avogadro's Number (6.0221421 x 1023).