answer:
Step-by-step explanation:
=> simplify the binomial denominators
=>
=> find the (lcm) least common multiplier of
=> lcm =
then multiply the fractions with the lcm:
=>apply the fraction rule
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Answers & Comments
answer:![\frac{3}{(x-1)(x+1)(x+2)} \frac{3}{(x-1)(x+1)(x+2)}](https://tex.z-dn.net/?f=%5Cfrac%7B3%7D%7B%28x-1%29%28x%2B1%29%28x%2B2%29%7D)
Step-by-step explanation:
=> simplify the binomial denominators
=>![\frac{1}{(x-1)(x+1)} - \frac{1}{(x+1)(x+2)} \frac{1}{(x-1)(x+1)} - \frac{1}{(x+1)(x+2)}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B%28x-1%29%28x%2B1%29%7D%20-%20%5Cfrac%7B1%7D%7B%28x%2B1%29%28x%2B2%29%7D)
=> find the (lcm) least common multiplier of
=> lcm =![(x-1)(x+1)(x+2) (x-1)(x+1)(x+2)](https://tex.z-dn.net/?f=%28x-1%29%28x%2B1%29%28x%2B2%29)
then multiply the fractions with the lcm:
=>apply the fraction rule
=>![\frac{x+2-(x-1)}{(x-1)(x+1)(x+2)} \frac{x+2-(x-1)}{(x-1)(x+1)(x+2)}](https://tex.z-dn.net/?f=%5Cfrac%7Bx%2B2-%28x-1%29%7D%7B%28x-1%29%28x%2B1%29%28x%2B2%29%7D)
=>![\frac{3}{(x-1)(x+1)(x+2)} \frac{3}{(x-1)(x+1)(x+2)}](https://tex.z-dn.net/?f=%5Cfrac%7B3%7D%7B%28x-1%29%28x%2B1%29%28x%2B2%29%7D)