1. The acceleration of the bicycle can be calculated using the formula:
acceleration = (final velocity - initial velocity) / time
Here, the initial velocity is 5 m/s, the final velocity is 20 m/s, and the time is 10 seconds.
Therefore, the acceleration of the bicycle is:
acceleration = (20 m/s - 5 m/s) / 10 s = 1.5 m/s²
2. The time for the ball to fall to the surface of the moon can be calculated using the formula:
distance = (1/2) (acceleration) ( time²)
Here, the acceleration is the acceleration of gravity on the moon, which is 1.62 m/s², and the distance is the height from which the ball is dropped, which is 1.50 m.
Therefore, the time for the ball to fall can be calculated as follows:
1.50 m = (1/2) * 1.62 m/s² * time²
time² = 1.50 m / (1/2 * 1.62 m/s²) = 0.9259 s²
time = √0.9259 s² = 0.963 s (rounded to three significant figures)
Therefore, the time for the ball to fall to the surface of the moon is approximately 0.963seconds.
Answers & Comments
Verified answer
Answer:
1. The acceleration of the bicycle can be calculated using the formula:
acceleration = (final velocity - initial velocity) / time
Here, the initial velocity is 5 m/s, the final velocity is 20 m/s, and the time is 10 seconds.
Therefore, the acceleration of the bicycle is:
acceleration = (20 m/s - 5 m/s) / 10 s = 1.5 m/s²
2. The time for the ball to fall to the surface of the moon can be calculated using the formula:
distance = (1/2) (acceleration) ( time²)
Here, the acceleration is the acceleration of gravity on the moon, which is 1.62 m/s², and the distance is the height from which the ball is dropped, which is 1.50 m.
Therefore, the time for the ball to fall can be calculated as follows:
1.50 m = (1/2) * 1.62 m/s² * time²
time² = 1.50 m / (1/2 * 1.62 m/s²) = 0.9259 s²
time = √0.9259 s² = 0.963 s (rounded to three significant figures)
Therefore, the time for the ball to fall to the surface of the moon is approximately 0.963 seconds.