Answer:
75°
Step-by-step explanation:
Inattach ko na po yung image nandon po yung diagram check mo nalang po eon
Since BCD is a right isosceles triangle,
From the given information, ABC is an equilateral triangle.
Hence,
Observe that:
Likewise,
Notice that
So,
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Answers & Comments
Answer:
75°
Step-by-step explanation:
Inattach ko na po yung image nandon po yung diagram check mo nalang po eon
Since BCD is a right isosceles triangle,![\sf \angle BCD = \frac{180^{\circ}-90^{\circ}}{2} = 45^{\circ}, \because BD = CD \ and \ BD \perp CD \sf \angle BCD = \frac{180^{\circ}-90^{\circ}}{2} = 45^{\circ}, \because BD = CD \ and \ BD \perp CD](https://tex.z-dn.net/?f=%5Csf%20%5Cangle%20BCD%20%3D%20%5Cfrac%7B180%5E%7B%5Ccirc%7D-90%5E%7B%5Ccirc%7D%7D%7B2%7D%20%3D%2045%5E%7B%5Ccirc%7D%2C%20%5Cbecause%20BD%20%3D%20CD%20%5C%20and%20%5C%20BD%20%5Cperp%20CD)
From the given information, ABC is an equilateral triangle.
Hence,![\sf \angle BCA = \angle ABC = \angle BAC = 60^{\circ} \sf \angle BCA = \angle ABC = \angle BAC = 60^{\circ}](https://tex.z-dn.net/?f=%5Csf%20%5Cangle%20BCA%20%3D%20%5Cangle%20ABC%20%3D%20%5Cangle%20BAC%20%3D%2060%5E%7B%5Ccirc%7D)
Observe that:
Hence,
Likewise,
Notice that![\sf BE \perp AC \sf BE \perp AC](https://tex.z-dn.net/?f=%5Csf%20BE%20%5Cperp%20AC)
So,