Answer:
2.
we can use,
t = k/n
where
t = 8
n = 5
8 = k/5
8 × 5 = k/5 × 5
40 = k
k = 40
so now we know:
t = 40/n
and when n = 10
t = 40/10
= 4
how many days could he finish a similar piece of work by working 10 hours a day?
10 = 40/n
n = 40/10
3.
50 = number of books
3 and 2 = terms in the ratio
5 = sum of the terms in the ratio
50 / 5 = 10
then multiply 10 by each of the term in the ratio
10 × 3 = 30 (math books)
10 × 2 = 20 (science books)
Final answer:
to check, add them all
30 + 20 = 50
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Answers & Comments
Answer:
2.
we can use,
t = k/n
where
t = 8
n = 5
8 = k/5
8 × 5 = k/5 × 5
40 = k
k = 40
so now we know:
t = 40/n
and when n = 10
t = 40/10
= 4
how many days could he finish a similar piece of work by working 10 hours a day?
10 = 40/n
n = 40/10
= 4
So, the carpenter needs 4 days to complete the job by working 10 hours a day.
3.
50 = number of books
3 and 2 = terms in the ratio
5 = sum of the terms in the ratio
50 / 5 = 10
then multiply 10 by each of the term in the ratio
10 × 3 = 30 (math books)
10 × 2 = 20 (science books)
Final answer:
30 and 20
to check, add them all
30 + 20 = 50