Answer:
KINETIC ENERGY (J)
KE = \frac{1}{2}mv^{2}KE=
2
1
mv
where: m = mass, kg; and v = velocity, m/s.
GIVEN:
m = 150 kg
v = 15 m/s
SOLUTION:
KE = \frac{1}{2}(150 kg)(15 m/s)^{2}KE=
(150kg)(15m/s)
KE = 1125 kg\frac{m}{s^{2}}KE=1125kg
s
m
ANSWER:
Kinetic energy is 1125 J.
Explanation:
Yan lang po
Copyright © 2024 EHUB.TIPS team's - All rights reserved.
Answers & Comments
Answer:
KINETIC ENERGY (J)
KE = \frac{1}{2}mv^{2}KE=
2
1
mv
2
where: m = mass, kg; and v = velocity, m/s.
GIVEN:
m = 150 kg
v = 15 m/s
SOLUTION:
KE = \frac{1}{2}mv^{2}KE=
2
1
mv
2
KE = \frac{1}{2}(150 kg)(15 m/s)^{2}KE=
2
1
(150kg)(15m/s)
2
KE = 1125 kg\frac{m}{s^{2}}KE=1125kg
s
2
m
ANSWER:
KINETIC ENERGY (J)
KE = \frac{1}{2}mv^{2}KE=
2
1
mv
2
where: m = mass, kg; and v = velocity, m/s.
GIVEN:
m = 150 kg
v = 15 m/s
SOLUTION:
KE = \frac{1}{2}mv^{2}KE=
2
1
mv
2
KE = \frac{1}{2}(150 kg)(15 m/s)^{2}KE=
2
1
(150kg)(15m/s)
2
KE = 1125 kg\frac{m}{s^{2}}KE=1125kg
s
2
m
ANSWER:
Kinetic energy is 1125 J.
Explanation:
Yan lang po