Pa help naman po dito. Malapit na kasi sumabog utak ko haha. Kung pwede rin pasamahan po ng solutions. Thank you ng maramii
Answers & Comments
elaifuentes11
1) The electron force between 2 electrons separated by 4*10^3m can be calculated using Coulomb's law: EF = k * (q1*q2)/r^2
where k is the Coulomb constant (k = 9x10^9 Nm^2/C^2), q1 and q2 are the charges of the electrons (q = -1.6x10^-19 C), and r is the distance between them (r = 4x10^3 m).
Plugging in the values, we get:
EF = (9x10^9 Nm^2/C^2) * (-1.6x10^-19 C)^2 / (4x10^3 m)^2
EF = -2.3x10^-28 N
Therefore, the magnitude of EF is 2.3x10^-28 N.
2) The charge on an electron is -1.6x10^-19 C. Therefore, to find the number of electrons in -6C of charge, we can use the formula: n = Q/q
where n is the number of electrons, Q is the total charge, and q is the charge on a single electron.
Plugging in the values, we get:
n = -6C / (-1.6x10^-19 C)
n = 3.75x10^19 electrons
To find the mass of these electrons, we can use the formula:
m = n * me
where m is the total mass, n is the number of electrons, and me is the mass of a single electron (me = 9.11x10^-31 kg).
Plugging in the values, we get:
m = (3.75x10^19 electrons) * (9.11x10^-31 kg/electron)
m = 3.42x10^-11 kg
Therefore, the total mass of these electrons is 3.42x10^-11 kg.
3) The force of repulsion between two magnesium ions can be calculated using Coulomb's law: F = k * (q1*q2)/r^2
where k is the Coulomb constant (k = 9x10^9 Nm^2/C^2), q1 and q2 are the charges of the ions (q = +2e = +3.2x10^-19 C for magnesium ions), and r is the distance between them (r = 4x10^-9 m).
Plugging in the values, we get:
F = (9x10^9 Nm^2/C^2) * (+3.2x10^-19 C)^2 / (4x10^-9 m)^2
F = 5.12x10^-8 N
Therefore, the force of repulsion between the magnesium ions is 5.12x10^-8 N.
4) To find the magnitude and direction of the force on charge Q, we can use Coulomb's law: F = k * (Qq1)/r1^2 + k * (Qq2)/r2^2
where k is the Coulomb constant (k = 9x10^9 Nm^2/C^2), Q is the charge on the test charge, q1 and q2 are the charges of the other two charges, r1 is the distance between Q and Q1, and r2 is the distance between Q and Q2.
Plugging in the values, we get:
F = (9x10^9 Nm^2/C^2) * (4x10^-6 C)*(8x10^-6 C) / (0.1 m)^2
Answers & Comments
EF = k * (q1*q2)/r^2
where k is the Coulomb constant (k = 9x10^9 Nm^2/C^2), q1 and q2 are the charges of the electrons (q = -1.6x10^-19 C), and r is the distance between them (r = 4x10^3 m).
Plugging in the values, we get:
EF = (9x10^9 Nm^2/C^2) * (-1.6x10^-19 C)^2 / (4x10^3 m)^2
EF = -2.3x10^-28 N
Therefore, the magnitude of EF is 2.3x10^-28 N.
2) The charge on an electron is -1.6x10^-19 C. Therefore, to find the number of electrons in -6C of charge, we can use the formula:
n = Q/q
where n is the number of electrons, Q is the total charge, and q is the charge on a single electron.
Plugging in the values, we get:
n = -6C / (-1.6x10^-19 C)
n = 3.75x10^19 electrons
To find the mass of these electrons, we can use the formula:
m = n * me
where m is the total mass, n is the number of electrons, and me is the mass of a single electron (me = 9.11x10^-31 kg).
Plugging in the values, we get:
m = (3.75x10^19 electrons) * (9.11x10^-31 kg/electron)
m = 3.42x10^-11 kg
Therefore, the total mass of these electrons is 3.42x10^-11 kg.
3) The force of repulsion between two magnesium ions can be calculated using Coulomb's law:
F = k * (q1*q2)/r^2
where k is the Coulomb constant (k = 9x10^9 Nm^2/C^2), q1 and q2 are the charges of the ions (q = +2e = +3.2x10^-19 C for magnesium ions), and r is the distance between them (r = 4x10^-9 m).
Plugging in the values, we get:
F = (9x10^9 Nm^2/C^2) * (+3.2x10^-19 C)^2 / (4x10^-9 m)^2
F = 5.12x10^-8 N
Therefore, the force of repulsion between the magnesium ions is 5.12x10^-8 N.
4) To find the magnitude and direction of the force on charge Q, we can use Coulomb's law:
F = k * (Qq1)/r1^2 + k * (Qq2)/r2^2
where k is the Coulomb constant (k = 9x10^9 Nm^2/C^2), Q is the charge on the test charge, q1 and q2 are the charges of the other two charges, r1 is the distance between Q and Q1, and r2 is the distance between Q and Q2.
Plugging in the values, we get:
F = (9x10^9 Nm^2/C^2) * (4x10^-6 C)*(8x10^-6 C) / (0.1 m)^2