The owner of the rectangular lot wants to put a fence around the area using 120-meter barb wire. The length of the rectangular lot is x. Express the area in square meters of the field.
The wire represents the perimeter of the lot=2(length+width)=120, or length+width=60, so, if length=x, x+width=60 and width=60-x metres. The area is length times width=x(60-x)=60x-x^2. We can write f(x)=60x-x^2 where area=f(x) in square metres.
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Answer:
The wire represents the perimeter of the lot=2(length+width)=120, or length+width=60, so, if length=x, x+width=60 and width=60-x metres. The area is length times width=x(60-x)=60x-x^2. We can write f(x)=60x-x^2 where area=f(x) in square metres.